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sparfa.py
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sparfa.py
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""" Sparse Factor Analysis was developed by Lan, Waters, Studer,
and Baraniuk (2014) to jointly infer student ability, item difficulty,
and item-to-concept relation (Q matrix) from response data.
This is an implementation of their approach in the sklearn/scipy
environment.
The original paper is here: https://www.jmlr.org/beta/papers/v15/lan14a.html
"""
# Sparse Factor Autoencoders for Item Response Theory
# Copyright (C) 2021-2022
# Benjamin Paaßen
# German Research Center for Artificial Intelligence
#
# This program is free software: you can redistribute it and/or modify
# it under the terms of the GNU General Public License as published by
# the Free Software Foundation, either version 3 of the License, or
# (at your option) any later version.
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
# You should have received a copy of the GNU General Public License
# along with this program. If not, see <https://www.gnu.org/licenses/>.
__author__ = 'Benjamin Paaßen'
__copyright__ = 'Copyright 2021-2022, Benjamin Paaßen'
__license__ = 'GPLv3'
__version__ = '0.1.0'
__maintainer__ = 'Benjamin Paaßen'
__email__ = 'benjamin.paassen@dfki.de'
import numpy as np
from sklearn.cluster import KMeans
from sklearn.impute import SimpleImputer
from sklearn.preprocessing import StandardScaler
from scipy.optimize import minimize
P_CLIP_ = 1E-8
P_CLIP_HI_ = 1. - P_CLIP_
LOGIT_CLIP_ = np.log(1. / P_CLIP_ - 1.)
class SPARFA:
""" A SPARFA model describes student responses via item response
theory with a Q matrix.
In particular, we model the probability of student i answering
correctly on item j via
p[i, j] = sigma(np.dot(theta[i, :], Q[j, :]) - b[j])
where theta[i, :] is the ability of student i on all
domain-relevant skills, Q[j, :] describes which skills are
relevant for item j, and b[j] is the difficulty of task j.
Sigma denotes the logistic function.
The model is learned via an alternating optimization.
We first fit Q[j, :] and b[j] for each item j and then
theta[i, :] for each student i. Each optimization is small
and, thus, fairly fast.
Parameters
----------
num_concepts: int
The number of skills or concepts in the domain.
num_iterations: int (default = 10)
The number of alternating optimization iterations.
l1regul: float (default = 0.1)
The L1 regularization strength to encourage sparsity in the
Q matrix.
l2regul: float (default = 1E-3)
The L2 regularization strength.
Attributes
----------
Q_: ndarray
A coupling matrix between items and concepts/skills, where
Q_[j, k] indicates how relevant concept k is for item j.
Q_ is encouraged to be sparse and forced to be non-negative.
b_: ndarray
The difficulty for each item.
Theta_: ndarray
An ability matrix where Theta_[i, k] indicates the ability
of student i on skill/concept k.
"""
def __init__(self, num_concepts, num_iterations = 10, l1regul = 0.1, l2regul = 1E-3):
self.num_concepts = num_concepts
self.num_iterations = num_iterations
self.l1regul = l1regul
self.l2regul = l2regul
def fit(self, X, Y = None, verbose = False, ignore_optimizer_failures = True):
""" Fits this model to the given response matrix.
Parameters
----------
X: ndarray
A matrix where X[i, j] = 1 if student i answered item j
correctly and X[i, j] = 0, otherwise.
"""
m = X.shape[0]
n = X.shape[1]
# initialize Q based on a clustering of responses
# impute nans first for that clustering
Ximp = SimpleImputer(missing_values = np.nan, strategy = 'mean').fit_transform(X)
clust = KMeans(n_clusters = self.num_concepts)
clust.fit(Ximp.T)
Q = np.zeros((n, self.num_concepts))
for k in range(self.num_concepts):
Q[clust.labels_ == k, k] = 1.
# initialize b as zeros
b = np.zeros(n)
# initialize student knowledge by counting the number
# of correct responses in each concept and z-normalizing
# the resulting count
Theta = np.dot(Ximp, Q)
Theta = StandardScaler().fit_transform(Theta)
# prepare aux variables
pos = X > 0.5
neg = X < 0.5
present = np.logical_not(np.isnan(X))
# now we can start the actual optimization loop
for it in range(self.num_iterations):
# optimize Q and b jointly via non-negative, l1 and l2
# regularized logistic regression. Note that we perform
# a separate optimization for each item
loss = 0.
for j in range(n):
# prepare the objective function for optimization
# of Q[j, :] and b[j]
posj = pos[:, j]
negj = neg[:, j]
presj = present[:, j]
xj = X[presj, j]
def objective(params):
qj = params[:-1]
bj = params[-1]
# compute logits
zj = np.dot(Theta, qj) - bj
# compute probabilities
pj = np.zeros_like(zj)
pj[zj > LOGIT_CLIP_] = P_CLIP_HI_
pj[zj < -LOGIT_CLIP_] = P_CLIP_
non_clipped = np.logical_and(zj <= LOGIT_CLIP_, zj >= -LOGIT_CLIP_)
pj[non_clipped] = 1. / (1. + np.exp(-zj[non_clipped]))
# compute loss
l = -np.sum(np.log(pj[posj])) -np.sum(np.log(1. - pj[negj])) + self.l2regul * np.sum(np.square(qj)) + self.l1regul * np.sum(qj)
# compute gradient
delta = pj[presj] - xj
grad = np.zeros_like(params)
grad[:-1] = np.dot(delta, Theta[presj, :]) + 2 * self.l2regul * qj + self.l1regul * np.ones_like(qj)
grad[-1] = -np.sum(delta)
return l, grad
# set up bounds
bounds = [(0., np.inf)] * (self.num_concepts) + [(-np.inf, np.inf)]
# optimize
res = minimize(objective, np.zeros(self.num_concepts + 1) , jac = True, bounds = bounds)
loss += res.fun
if not ignore_optimizer_failures and not res.success:
raise ValueError('optimization for item %d failed with message %s' % (j, res.message))
# store results and normalize every column (concept)
# by its maximum value
Q[j, :] = res.x[:-1]
b[j] = res.x[-1]
if verbose:
print('item loss after iteration %d: %g' % (it + 1, loss))
# opimize Theta based on current Q and b. We do that
# independently for each student
loss_ability = 0.
for i in range(m):
# prepare the objective function for optimization
# of Theta[i, :]
posi = pos[i, :]
negi = neg[i, :]
presi = present[i, :]
xi = X[i, presi]
Qi = Q[presi, :]
def objective(thetai):
# compute logits
zi = np.dot(thetai, Q.T) - b
# compute probabilities
pi = np.zeros_like(zi)
pi[zi > LOGIT_CLIP_] = P_CLIP_HI_
pi[zi < -LOGIT_CLIP_] = P_CLIP_
non_clipped = np.logical_and(zi <= LOGIT_CLIP_, zi >= -LOGIT_CLIP_)
pi[non_clipped] = 1. / (1. + np.exp(-zi[non_clipped]))
# compute loss
l = -np.sum(np.log(pi[posi])) - np.sum(np.log(1. - pi[negi])) + self.l2regul * np.sum(np.square(thetai))
# compute gradient
delta = pi[presi] - xi
grad = np.dot(delta, Qi) + 2 * self.l2regul * thetai
return l, grad
# optimize
res = minimize(objective, Theta[i, :], jac = True)
loss_ability += res.fun
if not ignore_optimizer_failures and not res.success:
raise ValueError('optimization for student %d failed with message %s' % (i, res.message))
Theta[i, :] = res.x
if verbose:
print('ability loss after iteration %d: %g' % (it + 1, loss_ability))
# # optimize Theta based on current Q and b. We do that in
# # one big chunk for the sake of computational efficiency.
# def objective(params):
# Theta = params.reshape((m, self.num_concepts))
# # compute logits
# Z = np.dot(Theta, Q.T) - np.expand_dims(b, 0)
# # compute probabilities
# P = np.zeros_like(Z)
# P[Z > LOGIT_CLIP_] = P_CLIP_HI_
# P[Z < -LOGIT_CLIP_] = P_CLIP_
# non_clipped = np.logical_and(Z <= LOGIT_CLIP_, Z >= -LOGIT_CLIP_)
# P[non_clipped] = 1. / (1. + np.exp(-Z[non_clipped]))
# # compute loss
# l = -np.sum(np.log(P[pos])) - np.sum(np.log(1. - P[neg])) + self.l2regul * np.sum(np.square(Theta))
# # compute gradient
# Delta = P - X
# Delta[np.isnan(X)] = 0.
# grad = np.dot(Delta, Q) + 2 * self.l2regul * Theta
# return l, np.ravel(grad)
# # start optimization
# res = minimize(objective, np.ravel(Theta), jac = True)
# print('ability loss after iteration %d: %g' % (it + 1, res.fun))
# if not res.success:
# raise ValueError('optimization for abilities failed with message %s' % res.message)
# Theta = res.x.reshape((m, self.num_concepts))
# store final results
self.Q_ = Q
self.b_ = b
self.Theta_ = Theta
def encode(self, X, ignore_optimizer_failures = True):
""" Infers the knowledge of each student based on their
given response patterns. Note that this function performs
an optimization.
Parameters
----------
X: ndarray
A response matrix where X[i, j] = 1 if student i answered
item j correctly and X[i, j] = 0, otherwise.
Returns
-------
Theta: ndarray
An ability matrix where Theta[i, k] indicates the ability
of student i on skill/concept k.
"""
m, n = X.shape
Theta = np.zeros((m, self.num_concepts))
for i in range(m):
# prepare the objective function for optimization
# of Theta[i, :]
posi = X[i, :] > 0.5
negi = X[i, :] < 0.5
presi = np.logical_not(np.isnan(X[i, :]))
xi = X[i, presi]
Qi = self.Q_[presi, :]
def objective(thetai):
# compute logits
zi = np.dot(thetai, self.Q_.T) - self.b_
# compute probabilities
pi = np.zeros_like(zi)
pi[zi > LOGIT_CLIP_] = P_CLIP_HI_
pi[zi < -LOGIT_CLIP_] = P_CLIP_
non_clipped = np.logical_and(zi <= LOGIT_CLIP_, zi >= -LOGIT_CLIP_)
pi[non_clipped] = 1. / (1. + np.exp(-zi[non_clipped]))
# compute loss
l = -np.sum(np.log(pi[posi])) - np.sum(np.log(1. - pi[negi])) + self.l2regul * np.sum(np.square(thetai))
# compute gradient
delta = pi[presi] - xi
grad = np.dot(delta, Qi) + 2 * self.l2regul * thetai
return l, grad
# optimize
res = minimize(objective, Theta[i, :], jac = True)
if not ignore_optimizer_failures and not res.success:
raise ValueError('optimization for student %d failed with message %s' % (i, res.message))
Theta[i, :] = res.x
return Theta
def decode(self, Theta):
""" Predicts correct responses for each student on
each item based on the given knowledge matrix.
Parameters
----------
Theta: ndarray
An ability matrix where Theta[i, k] indicates the ability
of student i on skill/concept k.
Returns
-------
X: ndarray
A response matrix where X[i, j] indicates the predicted
logit of the probability that student i answers correctly
on item j.
"""
# compute logits
Z = np.dot(Theta, self.Q_.T) - np.expand_dims(self.b_, 0)
# binarize
Z[Z <= 0.] = 0.
Z[Z > 0.] = 1.
return Z
def decode_proba(self, Theta):
""" Predicts repsonse probabilities for each student on
each item based on the given knowledge matrix.
Parameters
----------
Theta: ndarray
An ability matrix where Theta[i, k] indicates the ability
of student i on skill/concept k.
Returns
-------
P: ndarray
A matrix where P[i, j] indicates the predicted probability
of student i to answer item j correctly.
"""
# compute logits
Z = np.dot(Theta, self.Q_.T) - np.expand_dims(self.b_, 0)
# compute probabilities
P = np.zeros_like(Z)
P[Z > LOGIT_CLIP_] = P_CLIP_HI_
P[Z < -LOGIT_CLIP_] = P_CLIP_
non_clipped = np.logical_and(Z <= LOGIT_CLIP_, Z >= -LOGIT_CLIP_)
P[non_clipped] = 1. / (1. + np.exp(-Z[non_clipped]))
return P
def predict(self, X = None):
""" Predicts whether students will answer correctly on each
item according to the trained model.
Parameters
----------
X: ndarray (default = None)
A response matrix where X[i, j] = 1 if student i answered
item j correctly and X[i, j] = 0, otherwise.
If not given, the prediction is made on the training
data.
Returns
-------
X: ndarray
A response matrix where X[i, j] = 1 if student i is
preidcted to answer item j correctly and X[i, j] = 0,
otherwise.
"""
# compute knowledge
if X is None:
Theta = self.Theta_
else:
Theta = self.encode(X)
# decode
return self.decode(Theta)
def predict_proba(self, X = None):
""" Predicts whether students will answer correctly on each
item according to the trained model.
Parameters
----------
X: ndarray (default = None)
A response matrix where X[i, j] = 1 if student i answered
item j correctly and X[i, j] = 0, otherwise.
If not given, the prediction is made on the training
data.
Returns
-------
P: ndarray
A matrix where P[i, j] indicates the predicted probability
of student i to answer item j correctly.
"""
# compute knowledge
if X is None:
Theta = self.Theta_
else:
Theta = self.encode(X)
# decode
return self.decode_proba(Theta)
def Q(self):
return self.Q_
def difficulties(self):
return self.b_
## sample ground-truth knowledge, item difficulties, and Q matrix
#m = 100
#n = 20
#K = 5
#Theta = np.random.randn(m, K)
#Q = np.zeros((n, K))
#for j in range(n):
# Q[j, np.random.choice(K, size = 2, replace = False)] = np.random.rand(2)
#b = np.random.randn(n)
#Ztrue = np.dot(Theta, Q.T) - b
#Ptrue = 1. / (1. + np.exp(-Ztrue))
#Xtrue = np.random.rand(m, n)
#Xtrue[Xtrue >= 1. - Ptrue] = 1.
#Xtrue[Xtrue < 1. - Ptrue] = 0.
## include some nans
#for i in range(m):
# Xtrue[i, np.random.choice(n, size = 1)] = np.nan
## apply model
#model = SPARFA(K, num_iterations = 5, l2regul = 1.)
#model.fit(Xtrue)
## check accuracy
#X = model.predict()
#print('model error: %g' % np.nanmean(np.abs(X - Xtrue)))
## use hungarian algorithm to match learned concepts and
## ground truth concepts
#import matplotlib.pyplot as plt
#from scipy.optimize import linear_sum_assignment
#from scipy.spatial.distance import cdist
#Qnorm = model.Q_ / np.expand_dims(np.max(model.Q_, 0), 0)
#Costs = cdist(Q.T, Qnorm.T) ** 2
#rows, cols = linear_sum_assignment(Costs)
#plt.imshow(Costs[:, cols])
#plt.colorbar()
#plt.title('Q matrix distance (err: %g)' % np.sum(Costs[rows, cols]))
#plt.show()
## show relation between predicted item difficulty and success
## rate as well as predicted ability and success rate
#plt.figure(figsize=(16, 10))
#plt.subplot(2, 2, 1)
#plt.scatter(model.b_, b)
#plt.xlabel('predicted difficulty')
#plt.ylabel('actual difficulty')
#plt.subplot(2, 2, 2)
#plt.scatter(model.b_, np.nanmean(Xtrue, 0))
#plt.xlabel('predicted difficulty')
#plt.ylabel('success rate')
#plt.subplot(2, 2, 3)
#plt.scatter(np.mean(model.Theta_, 1), np.mean(Theta, 1))
#plt.xlabel('predicted mean ability')
#plt.ylabel('actual mean ability')
#plt.title('student ability')
#plt.subplot(2, 2, 4)
#plt.scatter(np.mean(model.Theta_, 1), np.nanmean(Xtrue, 1))
#plt.xlabel('predicted mean ability')
#plt.ylabel('success rate')
#plt.title('student ability')
#plt.show()